1/(n^2+6n+5)

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Solution for 1/(n^2+6n+5) equation: 


D( n )

n^2+6*n+5 = 0

n^2+6*n+5 = 0

n^2+6*n+5 = 0

n^2+6*n+5 = 0

DELTA = 6^2-(1*4*5)

DELTA = 16

DELTA > 0

n = (16^(1/2)-6)/(1*2) or n = (-16^(1/2)-6)/(1*2)

n = -1 or n = -5

n in (-oo:-5) U (-5:-1) U (-1:+oo)

1/(n^2+6*n+5) = 0

n^2+6*n+5 = 0

n^2+6*n+5 = 0

DELTA = 6^2-(1*4*5)

DELTA = 16

DELTA > 0

n = (16^(1/2)-6)/(1*2) or n = (-16^(1/2)-6)/(1*2)

n = -1 or n = -5

(n+5)*(n+1) = 0

1/((n+5)*(n+1)) = 0

n belongs to the empty set

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